added php example

README.md

@@ -28,10 +28,27 @@ https://your-url-and.path/api.php?[OPTIONS]&url=[WEBSITE_URL]
 
 The requested page will render as image (not provide a link). So you can use the path to your api.php file like so:
 
-```
+```html
 <img src="https://your-url-and.path/api.php?url=http://xkcd.com" title="screenshot of xkcd.com" />
 ```
 
+### Example php script to proxy an image to the local server
+
+```php
+<?php
+    $targeturl = 'http://www.xkcd.com';
+    $url = 'https://http2pic.haschek.at/api.php?url='.rawurlencode($targeturl);
+	    
+    $ch = curl_init($url);
+    $fp = fopen('xkcd.jpg', 'wb');
+    curl_setopt($ch, CURLOPT_FILE, $fp);
+    curl_setopt($ch, CURLOPT_HEADER, 0);
+    curl_exec($ch);
+    curl_close($ch);
+    fclose($fp);
+?>
+```
+
 ---
 
 This is a [HASCHEK SOLUTIONS](https://haschek.solutions) project